Quantity Based Questions with Solution for LIC Assistant

Time taken by C to complete the work =	20	= 10 days
	2

Time taken by A to complete the work alone = 10 + 2 = 12 days

Work done by A, B and C together in 1 day.

⇒	(	1	+	1	+	1	)	=	3 + 6 + 5	=	14
		20		10		12			60		60

this means if would take	30	days
	7

for A, B and C to complete the work together

∴ Time taken A, B and C to complete

7 works = 7 ×	30	days = 30 days
	7

Quantity : II Time taken by A to complete the work = 24 days

Time taken by B to complete the work = 30 days

Time taken by C to complete the work = 40 days

Work done by A and B in 1 day

⇒	(	1	+	1	)	=	5 + 4	=	9
		24		30			120		120

Work done by A and B in 6 days

= 6 ×	9	=	9
	120		20

Remaining work = 1 –	9	=	11
	20		20

Work done by A, B and C together in 1 day

=	(	1	+	1	+	1	)
		24		30		40

=	5 + 4 + 3	=	1
	120		10

Hence, A, B and C will complete the work in 10 days
 

Now, time taken by A, B and C to complete	11	of the work
	20

=	11	× 10 = 5.5 days
	20

Hence, Quantity I > Quantity II

Therefore, option (A) is correct.


4). Quantity I : A milkman sells one - third quantity of milk what he has at a profit of 6% and the remaining milk at a profit of 15%. What is the total profit per cent for the milkman?
Quantity I : Let total profit per cent = x%

By the rule of allegation-

⇒	15 – x	=	1
	x – 6		2

⇒ x = 12%

Quantity II : Let speed of boat is ‘a’ km/h and speed of stream is ‘b’ km/h.

According to question-

⇒	13.5	=	54	.. (1)
	a + b		60

⇒	13.5	= 1.5    .......(2)
	a – b

From (1) and (2)-

⇒ a = 12 and b = 3

Hence, option (E) is correct.


5). Quantity I: The distance travelled by a bus in 4 hours is 320 km. If the speed of bus is increased by 20% then what will be the time taken by bus to cover the triple of distance?  
A. Quantity : I > Quantity : II
B. Quantity : I ≥ Quantity : II
C. Quantity : I < Quantity : II
D. Quantity : II ≥ Quantity : I
E. Quantity I = Quantity II or relation can not be established

Ans: A

Explanation:-

Quantity : I

Distance travelled by the bus = 320 km

Time taken = 4 hours

∴ Speed of the bus =	320	= 80 km/hr
	4

Speed after 20% increment = 80 ×	120	= 96 km/hr
	100

Now distance need to travel = 320 × 3 = 960 km
 

∴Time take =	960	= 10 hours
	96

Quantity : II

Distance between point A and B = 150 km

half of distance = 75 km

Time taken to cover 75 km at a speed of 25 km/hr

=	75	= 3 hours
	25

Time taken to cover 75 km at a speed of 30 km/hr

=	75	= 2.5 hours
	30

And we also know that bus took 0.5 hour rest in between.

Therefore, total time = 3 hr + 2.5 hr + 0.5 hr = 6 hours

Here, Quantity I > Quantity II

Therefore, option  (A) is correct.
 

6). Quantity I: Speed of boat in still water, if a man can travel 54 km downstream in 9 hours and 40 km upstream in 10 hours.  
A. Quantity I ≤ Quantity II
B. Quantity I ≥ Quantity II
C. Quantity I > Quantity II
D. Quantity I < Quantity II
E. Quantity I = Quantity II

Ans: C

Explanation:-

Quantity I:

Let speed of boat = x kmph, speed of stream = y kmph

upstream speed = x – y, downstram speed = x + y

x + y =	54
	9

x + y = 6 ....1
 

x – y =	40
	10

x – y = 4 ....2

equation 1 + equation 2

x = 5

speed of boat = 5 kmph

Quantity II:

Let speed of boat = x kmph, speed of stream = 1 kmph

downstream speed = x + 1

45	= x + 1
9

5 – 1 = x

x = 4

Speed of boat = 4 kmph

Quantity I > Quantity II

Hence, option C is correct.


7). Quantity I: Age of mother, if the age of Smiti is 1/7th of her mother's age and after 5 years Smiti's age will be 12 years. Ans: E

Explanation:-

Quantity I:

Smiti's age after 5 years = 12 years

Present age of Smiti = 7 years

Mother's age	= Smiti's age
7

Mother's age = 7 × 7 = 49 years

Quantity II:   Let Sukriti's age = 3x, Mother's age = 7x

According to the statement,

3x + 3 : 7x + 3 = 6 : 13

13 (3x + 3) = 6 (7x + 3)

39x + 39 = 42x + 18

39 – 18 = 42x – 39x

21 = 3x

x = 7

Mother's age = 7 × 7 = 49 years

Quantity I = Quantity II

Hence, option E is correct.


8). What is the area of the rectangle?
Ans:

Explanation:-

Quantity I:

Area of the square = 24 × 24 

= 576 cm²

Area of the square = Area of the rectangle

Area of the rectangle = 576 cm²

Quantity II:

Length of the rectangle = 6x, Breadth = 5x

Perimeter = 88

2 (l + b) = 88

6x + 5x = 44

11x = 44

x = 4

Length = 24cm, breadth = 20cm

Area of the rectangle = 24 × 20

= 480 cm²

Quantity I > Quantity II

Hence, option E is correct.


9). Quantity I: Selling price, if cost price is Rs. 50,000 and profit is 20%
Quantity I :

SP =	120	× 50000 = Rs.60000
	100

Quantity II :

Discount = 25% =	1	(MP = 4, SP = 4 – 1 = 3)
	4

Gain =	50	% =	1	(CP = 6, SP = 6 + 1 = 7)
	3		6

Make SP same

CP…………SP…………..MP

18………….21………….28

18 = 50000

So 21 = Rs. 58333.33

Hence, Quantity I > Quantity II

Therefore, option (A) is correct.


10). Quantity :I  5 years ago, the ratio of Seema and Meera's age was 8 : 5. Two years hence, the ratio of their ages will becomes 5 : 4 Find the present age of Meera.  
A. Quantity : I > Quantity : II
B. Quantity : I ≥ Quantity : II
C. Quantity : I < Quantity : II
D. Quantity : II ≥ Quantity : I
E. Quantity I = Quantity II or relation can not be established
 
Ans: C

Explanation:-

Quantity : I

Let the present ages of seema and meean are s and m respectively.

Now,

s – 5	=	8
m – 5		5

⇒ 8m – 40 = 5s – 25

⇒	8m –15	= s ......(i)
	5

And,

s + 2	=	5
m + 2		4

⇒ 5m + 10 = 4s + 8

⇒ s =	5m + 2	.......(ii)
	4

equating (i) and (ii), we get

8m – 15	=	5m + 2
5		4

⇒ m = 10 Hence, the present age of meera is 10 years.

Quantity : II

Let, the present ages of Son, mother and sister are s, m and sis.

Now, 2s = m ............(i)

And, sis = 20 years ............(ii)

m = 2 sis ...........(iii)

Using equation (ii) and (iii), we can say that

m = 40 years ............(iv)

Using (iv) and (i),

we can say that s = 20 years.

Here, Quantity: I < Quantity II

Hence, option (C) is correct.

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