Quantity Based Questions with Solution for LIC Assistant
Hello Aspirants,
On this page, you can practice important Quantity Based Questions for LIC Assistant for free so you can give a better performance in your upcoming LIC Assistant exam. In this article we are also providing Quantity Based Questions PDF in the form of quizzes so practice Maths Inequality questions in offline mode too.
As you know most of the students like to solve Data Interpretation, Simplification and Number Series Etc. questions but if you practice Quantity Based Questions then you will make yourself different from 60% of aspirants, you can score high in your LIC Assistant.
Quantity Based Questions have 50% chance to appear in your LIC Assistant Pre but they have high chance to appear in LIC Assistant Mains Exam. So in this article you will get all level of Quantity Based Questions in the form of quizzes and PDF too.
Aspirant always keep one thing in his mind that you must practice Maths Inequality Questions as much as you can either in the form of online quizzes or offline PDF whatever suitable for you. This will enhance your solving skills which will help you to gain extra marks in your LIC Assistant exam.
So, here Smartkeeda providing Maths Inequality Questions Quizzes and PDF for LIC Assistant for free. In these PDFs you will see various types of Maths Inequality Questions, some are new pattern based and some are frequently asked in LIC Assistant or in similar exams. So Download Maths Inequality Questions PDF for LIC Assistant.
As you know around five questions of Maths Inequality can be asked in LIC Assistant, therefore while downloading Quantity Based Questions PDF for Insurance clerk level exams like LIC Assistant, you need to brush up your maths arithmetic or maths word problems skills;
Here are the some important Quantity Based Questions with solution for LIC Assistant.
1). In an envelope there are 5 green, 3 yellow and 4 pink tablets. 3 tablets are picked at random.
Quantity I: The probability that 2 tablets are yellow in colour and 1 tablet is pink in colour.
Quantity II: The probability that all the tablets are green in colour.
A. Quantity I > Quantity II
B. Quantity I < Quantity II
C. Quantity I = Quantity II
D. Quantity I ≤ Quantity II
E. Quantity I ≥ Quantity II
Ans:A
Explanation:-
Favourable outcomes:
2 yellow + 1 pink tablet = 3C2 × 4C1
= 12
Total outcomes = 12C3
= 220
| Probability = | 12 | = | 3 |
| 220 | 55 |
Quantity II:
Favourable outcomes:
3 green tablet = 5C3
= 10
Total outcomes = 12C3
= 220
| Probability = | 10 | = | 1 |
| 220 | 22 |
Quantity I > Quantity II
Hence, option A is correct.
2). Find the percentage of boys in the class this year.
Quantity I: This year the percentage of girls in the class is 60%.
Quantity II: Last years out of the 300 students, 50% was girls and this year the number of girls are increased by 10% but total students remains same.
Ans: B
Explanation:-
Quantity I:
Because percentage of girls = 60%,
So the percentage of boys = 100 – 60% = 40%
Quantity II:
Last year,
Girls was 300 × 50% = 150, boys = 300 × 50% = 150
This year, because girls are increased by 10% and total students remain same.
girls = 150 × 110% = 165, boys = 300 – 165 = 135
| % of boys = | 135 | × 100 = 45% |
| 300 |
Quantity I < Quantity II
Hence, option B is correct.
3). Quantity I : Working alone, B can complete the work in 20 days. C is twice as efficient as B and A takes 2 days more than it takes C to complete the work. Working together, in how much time would they be able to complete 7 such works?
Ans: A
Explanation:-
Time taken by B to complete the work = 20 days
| Time taken by C to complete the work = | 20 | = 10 days |
| 2 |
Time taken by A to complete the work alone = 10 + 2 = 12 days
Work done by A, B and C together in 1 day.
| ⇒ | ( | 1 | + | 1 | + | 1 | ) | = | 3 + 6 + 5 | = | 14 |
| 20 | 10 | 12 | 60 | 60 |
| this means if would take | 30 | days |
| 7 |
for A, B and C to complete the work together
∴ Time taken A, B and C to complete
| 7 works = 7 × | 30 | days = 30 days |
| 7 |
Quantity : II Time taken by A to complete the work = 24 days
Time taken by B to complete the work = 30 days
Time taken by C to complete the work = 40 days
Work done by A and B in 1 day
| ⇒ | ( | 1 | + | 1 | ) | = | 5 + 4 | = | 9 |
| 24 | 30 | 120 | 120 |
Work done by A and B in 6 days
| = 6 × | 9 | = | 9 |
| 120 | 20 |
| Remaining work = 1 – | 9 | = | 11 |
| 20 | 20 |
Work done by A, B and C together in 1 day
| = | ( | 1 | + | 1 | + | 1 | ) |
| 24 | 30 | 40 |
| = | 5 + 4 + 3 | = | 1 |
| 120 | 10 |
Hence, A, B and C will complete the work in 10 days
| Now, time taken by A, B and C to complete | 11 | of the work |
| 20 |
| = | 11 | × 10 = 5.5 days |
| 20 |
Hence, Quantity I > Quantity II
Therefore, option (A) is correct.
4). Quantity I : A milkman sells one - third quantity of milk what he has at a profit of 6% and the remaining milk at a profit of 15%. What is the total profit per cent for the milkman?
Ans: E
Explanation:-
Quantity I : Let total profit per cent = x%
By the rule of allegation-
| ⇒ | 15 – x | = | 1 |
| x – 6 | 2 |
⇒ x = 12%
Quantity II : Let speed of boat is ‘a’ km/h and speed of stream is ‘b’ km/h.
According to question-
| ⇒ | 13.5 | = | 54 | .. (1) |
| a + b | 60 |
| ⇒ | 13.5 | = 1.5 .......(2) |
| a – b |
From (1) and (2)-
⇒ a = 12 and b = 3
Hence, option (E) is correct.
5). Quantity I: The distance travelled by a bus in 4 hours is 320 km. If the speed of bus is increased by 20% then what will be the time taken by bus to cover the triple of distance?
Quantity II: A bus which is travelling from point A to point B which are 150 km apart, covers half of distance with 25 km/h and rest of distance with 30 km/hr and take rest of 30 minutes after travelling half of distance then what will be the total time taken by bus to reach destination?
A. Quantity : I > Quantity : II
B. Quantity : I ≥ Quantity : II
C. Quantity : I < Quantity : II
D. Quantity : II ≥ Quantity : I
E. Quantity I = Quantity II or relation can not be established
Ans: A
Explanation:-
Quantity : I
Distance travelled by the bus = 320 km
Time taken = 4 hours
| ∴ Speed of the bus = | 320 | = 80 km/hr |
| 4 |
| Speed after 20% increment = 80 × | 120 | = 96 km/hr |
| 100 |
Now distance need to travel = 320 × 3 = 960 km
| ∴Time take = | 960 | = 10 hours |
| 96 |
Quantity : II
Distance between point A and B = 150 km
half of distance = 75 km
Time taken to cover 75 km at a speed of 25 km/hr
| = | 75 | = 3 hours |
| 25 |
Time taken to cover 75 km at a speed of 30 km/hr
| = | 75 | = 2.5 hours |
| 30 |
And we also know that bus took 0.5 hour rest in between.
Therefore, total time = 3 hr + 2.5 hr + 0.5 hr = 6 hours
Here, Quantity I > Quantity II
Therefore, option (A) is correct.
6). Quantity I: Speed of boat in still water, if a man can travel 54 km downstream in 9 hours and 40 km upstream in 10 hours.
Quantity II: Speed of boat in still water, if a man can travel 45 km downstream in 9 hours and the speed of stream is 1 kmph.
A. Quantity I ≤ Quantity II
B. Quantity I ≥ Quantity II
C. Quantity I > Quantity II
D. Quantity I < Quantity II
E. Quantity I = Quantity II
Ans: C
Explanation:-
Quantity I:
Let speed of boat = x kmph, speed of stream = y kmph
upstream speed = x – y, downstram speed = x + y
| x + y = | 54 |
| 9 |
x + y = 6 ....1
| x – y = | 40 |
| 10 |
x – y = 4 ....2
equation 1 + equation 2
x = 5
speed of boat = 5 kmph
Quantity II:
Let speed of boat = x kmph, speed of stream = 1 kmph
downstream speed = x + 1
| 45 | = x + 1 |
| 9 |
5 – 1 = x
x = 4
Speed of boat = 4 kmph
Quantity I > Quantity II
Hence, option C is correct.
7). Quantity I: Age of mother, if the age of Smiti is 1/7th of her mother's age and after 5 years Smiti's age will be 12 years.
Ans: E
Explanation:-
Quantity I:
Smiti's age after 5 years = 12 years
Present age of Smiti = 7 years
| Mother's age | = Smiti's age |
| 7 |
Mother's age = 7 × 7 = 49 years
Quantity II: Let Sukriti's age = 3x, Mother's age = 7x
According to the statement,
3x + 3 : 7x + 3 = 6 : 13
13 (3x + 3) = 6 (7x + 3)
39x + 39 = 42x + 18
39 – 18 = 42x – 39x
21 = 3x
x = 7
Mother's age = 7 × 7 = 49 years
Quantity I = Quantity II
Hence, option E is correct.
8). What is the area of the rectangle?
Ans:
Explanation:-
Quantity I:
Area of the square = 24 × 24
= 576 cm2
Area of the square = Area of the rectangle
Area of the rectangle = 576 cm2
Quantity II:
Length of the rectangle = 6x, Breadth = 5x
Perimeter = 88
2 (l + b) = 88
6x + 5x = 44
11x = 44
x = 4
Length = 24cm, breadth = 20cm
Area of the rectangle = 24 × 20
= 480 cm2
Quantity I > Quantity II
Hence, option E is correct.
9). Quantity I: Selling price, if cost price is Rs. 50,000 and profit is 20%
Quantity I :
| SP = | 120 | × 50000 = Rs.60000 |
| 100 |
Quantity II :
| Discount = 25% = | 1 | (MP = 4, SP = 4 – 1 = 3) |
| 4 |
| Gain = | 50 | % = | 1 | (CP = 6, SP = 6 + 1 = 7) |
| 3 | 6 |
Make SP same
CP…………SP…………..MP
18………….21………….28
18 = 50000
So 21 = Rs. 58333.33
Hence, Quantity I > Quantity II
Therefore, option (A) is correct.
10). Quantity :I 5 years ago, the ratio of Seema and Meera's age was 8 : 5. Two years hence, the ratio of their ages will becomes 5 : 4 Find the present age of Meera.
Quantity :II The age of son is half the age of mother. His sister’s age is 20 years. Age of the mother is twice the age of his sister. Find the age of the son.
A. Quantity : I > Quantity : II
B. Quantity : I ≥ Quantity : II
C. Quantity : I < Quantity : II
D. Quantity : II ≥ Quantity : I
E. Quantity I = Quantity II or relation can not be established
Ans: C
Explanation:-
Quantity : I
Let the present ages of seema and meean are s and m respectively.
Now,
| s – 5 | = | 8 |
| m – 5 | 5 |
⇒ 8m – 40 = 5s – 25
| ⇒ | 8m –15 | = s ......(i) |
| 5 |
And,
| s + 2 | = | 5 |
| m + 2 | 4 |
⇒ 5m + 10 = 4s + 8
| ⇒ s = | 5m + 2 | .......(ii) |
| 4 |
equating (i) and (ii), we get
| 8m – 15 | = | 5m + 2 |
| 5 | 4 |
⇒ m = 10 Hence, the present age of meera is 10 years.
Quantity : II
Let, the present ages of Son, mother and sister are s, m and sis.
Now, 2s = m ............(i)
And, sis = 20 years ............(ii)
m = 2 sis ...........(iii)
Using equation (ii) and (iii), we can say that
m = 40 years ............(iv)
Using (iv) and (i),
we can say that s = 20 years.
Here, Quantity: I < Quantity II
Hence, option (C) is correct.
| Quiz 1 | Quiz 2 | Quiz 3 |
| Quiz 4 | Quiz 5 | Quiz 6 |
| Quiz 7 | Quiz 8 | Quiz 9 |
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