**Answer:** Option **
B **

**Explanation:**

First we find the day on 1.04.2005

1.04.2005 = (2004 years + period From 1.01.2005 to 1.04.2005)

Odd days in 2000 years = 0

4 years = (1 leap year + 3 ordinary years)

= (1 × 2 + 3 × 1) odd days = 5 odd days

Jan Feb Mar Apr

31 + 28 + 31 + 1 = 91 days = (13 weeks) = 0 odd day

Total number of odd days = (0 + 5) = 5 odd days

Odd days : 1st 2nd 3rd 4th 5th

Days : Mon Tue Wed Thu Fri

Frdiay was on 1.04.2005 , so Tuesday lies on 5.04.2005

Hence, Tuesday lies on 5th of April, 2005.